Jarvis needs to determine the distance across a lake. However, he can't measure this distance directly over the water. So, he set up a situation where he could use the measurements of two similar triangles to find the distance across the lake.
He selects a point X such that XZ is perpendicular to VZ, where V is a point at the other end of the lake. He then picks a point Y
on XZ. From point Y, he finds point W on XV such that WY is parallel to VZ.
If XY = 2,148 feet, WY = 1,074 feet, and XZ = 6,444 feet, what is the length of VZ, the distance across the lake?
A.
358 feet
B.
269 feet
C
4,296 feet
D
3,222 feet

$649.60

step-by-step explanation:

wertyujhgfdcvb

step-by-step explanation:

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w