Joyti cut a 21 m long rope into pieces of 7/2 m length each. How many pieces of the rope did she get?

It is given that Sunita cuts a 21-metre long rope into 7/2 metre long pieces .

Total length of rope = 21 m

Total length of rope = 21 m Number of cut - pieces = 7/2 m

Let Required Number of pieces be x

Step-by-step explanation:

☞ 21 = x × 7/2

☞ 21 × 2 = 7x

☞ 42 = 7x

☞ x = 42/7

☞ x = 6

Therefore, Required Number of pieces of rope are 6.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)