How to solve using Substitution or Elimination??? Help!!!
y=3x-1

y=2x+2

x=3

y=8

Step-by-step explanation:

the given equations are y=3x-1 (1)

and y=2x+2(2)

Using substitution method,

and solving y=3x-1

y+1=3x

or y+1/3 =x (3)

Putting the value of x= y + 1 / 3 in equation 2

y= 2x+2

or, y = 2 ( y + 1/3) +2

or, y= 2y + 2 / 3 +2

or, y = 2y + 2 + 6 // 3 ( Taking LCM)

Or, 3 y = 2y + 2 + 6 ( the denominator gets multiplied to y)

OR, 3 Y - 2Y =6 PLUS 2

or y = 8

therefore, y=8

now substituting the value of y=8 in equation (3)

y + 1 /3 = x

or ,,, 8 plus 1 by 3 =x

or 9 by 3 =x

Therefore, x is 3

a .4y4

hope this !