Maurice has a paper bag with three hard candies: two blueberries and one green apple. Yvonne and Kate ask if they can each have one. Yvonne closes her eyes and picks a candy from the bag, hoping for a blueberry. What are the chances she will pick a blueberry candy?

The chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.

Step-by-step explanation:

Maurice has a paper bag  with three hard candies

2 blueberries and 1 green apple

Yvonne and Kate want 1 candy each

It is not mentioned that ether Kate has taken a candy already before Yvonne or not so we will consider both the cases

Case 1

If Kate has picked a candy before Yvonne

Case 2

If Kate has not taken any candy from the bag before Yvonne

Probability that Yvonne will get a blueberry candy will be = 2/3

Therefore the chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

146%

step-by-step explanation: