Online photos: A poll surveyed internet users and found that of them had posted a photo or video online. Can you conclude that less than half of internet users have posted photos or videos online? Use the α 0.01 level of significance and the P-value method with the TI-84 calculator. 1. State the appropriate null and alternate hypotheses.
2. Compute the P-value.

Complete question :

Online photos: A poll surveyed 1765 internet users and found that 865 of them had posted a photo or video online. Can you conclude that less than half of internet users have posted photos or videos online? Use the α 0.01 level of significance and the P-value method with the TI-84 calculator.

1. State the appropriate null and alternate hypotheses.

2. Compute the P-value.

H0 : p = 0.5

H1 : p < 0.5

P value = 0.200454

Step-by-step explanation:

Given that :

Claim : Less than half internet users have posted photos or videos online.

Sample Proportion (p) = 865 / 1765 = 0.4900

The null hypothesis : H0 : p = 0.5 (that is half of internet users have posted photos online.

The alternative hypothesis : H1 : p < 0.5 (that is less than half of internet users have posted photo or video ;

P = 0.5

q = 1 - 0.5 = 0.5

The test statistic :

Z = p - p0 / sqrt(p0 * (q/n))

Z = (0.49 - 0.5) / sqrt(0.5 * (0.5/1765))

Z = - 0.01 / sqrt(0.5 *0.0002832)

Z = - 0.01 / sqrt(0.0001416)

Z = - 0.01 / 0.0119013

Z = - 0.8402443

The corresponding p value from the z statistic score at α = 0.01

= 0.200454

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5