Now suppose that the manufacturer decides to accept the shipment if there is at most one defective part in the sample. How large does K have to be to ensure that the probability that the manufacturer accepts an unacceptable shipment is less than 0.1?

hello your question is incomplete below is the missing parts of the question

answer : K = 80

Step-by-step explanation:

P [ x ≤ 1 ]  < 0.1

determine how large k have to be

note : n = k

sample proportion = 0.01

E = 0.05 - 0.01 = 0.04

applying this formula below

E =  

0.04 = 1.645    make n subject of the equation

n = 80.3353

hence  the value of K ≈ 80

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

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step-by-step explanation: