The height of a firework shot upward from the ground with the initial velocity of 10meters per second is represented by the function h(t) = - 16t2 + 4t How long did it take the firework to reach the ground

0.375 seconds

Step-by-step explanation:

In simple terms, to find the time it took to reach the ground, we need to find t from the equation.

If we differentiate h with respect to t we will get the velocity with which the fireworks is moving at.

We can now equate this to its velocity and solve for t

10 = -32t +4

t = 0.1875 ( time cannot be negative in value, so we ignore the negative sign)

Therefore, the time it took the fireworks to reach the ground is = 2 x 0.1875= 0.375 seconds.

(We need to account for the fact that the fireworks went up and came down)

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions