A local service agency hires you to estimate the average annual income of all 700 families living in a four square block section. Since time and funds are limited, yu take a random sample of 50 families and want the estimate to have a 92% confidence level. The 50 families had an average income of $35,300. Research shows the population standard deviation for annual income in this four square block section is $1,800

The true estimate of  the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval below

Step-by-step explanation:

From the question we are told that

    The  sample size is  n =  50  

    The sample mean is

     The population standard deviation is  

From the question we are told the confidence level is  92% , hence the level of significance is    

=>  

Generally from the normal distribution table the critical value  of   is  

Generally the margin of error is mathematically represented as  

=>  

=>  

Generally 92% confidence interval is mathematically represented as  

=>

=>

So the true estimate of  the average annual income of all 700 families living in a four square block section lies within the 92% confidence interval

16

step-by-step explanation:

answer: 33 ( approx)

step-by-step explanation:

since, in the linear regression formula, the slope is the a in the equation y = b + ax ( by comparing it with the general equation of line y = mx + c )

where,

here given table is,

price ($), x   :           18         23       25       29       30       33

pairs sold, y :         16         13         10       8         6       2

so, ,   ,   ,

and   ,

thus, slop of the given line is,

⇒  

⇒   ≈ 33