Find an equation of the line that passes through (3,10) and is parallel to the line x-3y=1

x - 3y = -27

Step-by-step explanation:

Two parallel lines have equations of the same form; only the constants differ.

Thus, if the given line is x - 3y = 1, the desired new line has equation of the form x - 3y = C, where we must find the value of C.

Substituting 3 for x and 10 for y in x - 3y = C, we get    3 - 3(10) = C, or

3 - 30 = C.  Thus, C = -27 and the desired new line is    x - 3y = -27.  

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.