Write a system of equations with the solution (5, 2).

This is one of those questions where they are just trying to confuse you by giving so many possibilities.

(-5, 2) Since (x, y)
x = -5
y = 2

a(x) + b(y) = s a(-5) + b(2) = s
c(x) + d(y) = t c(-5) + d(2) = t

Let's say a = 1, b = -2, c = 4, d = 5. These choices are random since it will work for any numbers.
You just need to solve the totals s and t
x - 2y = s -5 - 2(2) = -9 -5 - 4 = -9 s = -9
4x + 5y = t 4(-5) + 5(2) = -10 -20 + 10 = -10 t = -10

One of any number of solutions
x - 2y = -9
4x + 5y = -10

Solving the system we can show we will end up with our original solution
13y = 26 y = 2x - 4 = -9 x = -5
(-5, 2)

Hello!

the answer is:

the answer is:

why?

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!