The table shows the results of rolling a number cube, with sides labeled 1 through 6, several times. What is the experimental probability of rolling a 1 or a 5?

Outcome Number of times outcome occurred
1 10
2 6
3 4
4 8
5 6
6 6

we are given a event of rolling as die several times:

Outcome:                                         [1 2 3 4 5 6]

Number of times outcome occurred: [10    6 4 8 6 6]

We have to find the experimental probability of rolling a 1 or a 5

number of times 1 or 5 came up= 10+6=16

and total number of outcomes=  10+6+4+8+6+6=  40

P( rolling a 1 or a 5)=  

number of times 1 or 5 came up/ total number of outcomes

=   16/40

= 2/5

Hence, the experimental probability of rolling a 1 or a 5 is:

   2/5

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb