Parents are having twin babies and have put 7 unique name cards in a bowl. * When the first baby is born, a parent draws a card and gives the baby that name.

* When the second baby is born, the parent draws a card from the remaining names.

How many combinations of names were possible for those two babies?

42 Hope this helps!

Step-by-step explanation:

Okay so if there are 7 names lets just say the names are

1

2

3

4

5

6

7

The combos on names can be

1,2

1,3

1,4

1,5

1,6

1,7

2,1

2,3

2,4

2,5

2,6

2,7

3,1

3,2

3,4

3,5

3,6

3,7

4,1

4,2

4,3

4,5

4,6

4,7

5,1

5,2

5,3

5,4

5,6

5,7

6,1

6,2

6,3

6,4

6,5

6,7

7,1

7,2

7,3

7,4

7,5

7,6

There are 42 combos that can happen!

.25

step-by-step explanation:

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.