A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both sides and two-inch margins at the bottom and top, what are the dimensions of the smallest piece of paper (by area) that can be used? Choose 1

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Let the dimension of the paper be x and y;

Such that:

So:

Substitute 128 for Area

Make x the subject

When 1 inch margin is at top and bottom

The length becomes:

When 2 inch margin is at both sides

The width becomes:

The New Area (A) is then calculated as:

Substitute for x

Open Brackets

Collect Like Terms

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

Set

This gives:

Collect Like Terms

Multiply through by

Divide through by 2

Take square roots of both sides

Recall that:

Recall that the new dimensions are:

So:

To double-check;

Differentiate A'

The above value is:

This means that the calculated values are at minimum.

Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

step-by-step explanation:

2/4 is the answer

step-by-step explanation:

x= total pieces

both ate 9 pieces

mindy ate 3 so troy ate 6

6= (1/4)x

x =24