AD is a diameter of circle ABCDE . Angle BAC=22° & angle ADC=60°. AE and ED are parallel lines. Find the values of w, x, y,and z

x = 22°

w = 30°

y = 30°

z = 52°

Step-by-step explanation:

From ΔACD,

AD is the diameter and ∠ACD is the angle subtended by the diameter.

Therefore, m∠ACD = 90°

By triangle sum theorem,

m∠DAC + m∠ACD + m∠CDA = 180°

w° + 90° + 60° = 180°

w = 180 - 150

w = 30°

AB║ED and AD is a transversal line.

Therefore, m∠BAD = m∠ADE

(w + 22)° = z°

30 + 22 = z

z = 52°

Since, ∠CEB and ∠BAC are the inscribed angles subtended by the same arc BC,

Therefore, m∠CEB = m∠BAC

x = 22°

Similarly, ∠CED and ∠DAC are the inscribed angles subtended by the same arc CD,

m∠CED = m∠DAC = 30°

y = 30°

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

the answer is 0052

0 0 5 2

5 0 2 6 3 5

− 0

2 6

− 0

2 6 3

− 2 5 0

1 3 5

− 1 0 0

3 5