What are the solutions of the following system?
x^2+y^2=25
2x+y=-5
a. (0, –5) and (–5, 5)
b.(0, –5) and (5, –15)
c.(0, –5) and (–4, 3)
d.(0, –5) and (4, –13)

Option C is correct

the solution for the given system of equation is, (0, -5) and (-4, 3)

Step-by-step explanation:

Using identity:

Given the equation:

       .....[1]

              .....[2]

We can write [2] as:

Substitute this in [1] we have;

Using identity rule;

Combine like terms;

Subtract 25 from both sides we have;

⇒

By zero product property we have;

x = 0 and x+4 = 0

x = 0 and x = -4

Substitute these in [2] we have;

for x = 0

2(0)+y = -5

⇒

For x = -4 ,

-8+y = -5

add 8 to both sides we have;

y = 3

Therefore, the solution for the given system of equation is, (0, -5) and (-4, 3)

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.

1/6

step-by-step explanation: