Suppose a population of 10 spiders doubles in size every month. How many spiders will there be after 1 year? (5pts)
(a) 10,628,820
(b) 40,960
(c)81,920
(d) 5,314,410

b. 40,960

Step-by-step explanation:

There is probably some equation you could do for this but I find it simpler just to take 10 and multiply it by 2 and then keep multiplying the answers by 2 twelve times so:

10*2=20

20*2=40

40*2=80

80*2=160

160*2=320

320*2=640

640*2=1280

1280*2=2560

2560*2=5120

5120*2=10240

10240*2=20480

20480*2=40960

they used 313 gallons of paint

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.