Defects in computer hard-drives will usually render the entire computer worthless. For a particular model, the percent defective in the past has been 1%. If a sample size of 400 is taken, what would the 95.5% lower control chart limit be?

The 95.5% lower control chart limit be is 0.0005.

Given,

The average fraction percent in the past defective as p = 1%  = 0.01

Sample size N = 400

Then ,

According to the question ,

95.5% deviation = 2x

We have,

x =

We put these values, into the formula,

x =

=

=

= 0.0000245

The LCL = p - 2x

= 0.01 - 0.0000245

= 0.00005

The Lower control chart limit be is 0.00005

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0.00005

Step-by-step explanation:

We have the average fraction defective as p = 1%

= 0.01

N = 100

Then 95.5% deviation = 2σ

From there we have,

σ = √p*(1-p)/n

When we input these values, into the formula, we will have

σ = √0.01(1-0.01)/100

= √0.01(0.99)/100

= √0.000099

= 0.00995

The LCL = p - 2σ

= 0.01 - 0.00995

= 0.00005

lower control chart limit be is 0.00005

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

answer

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step-by-step explanation: