Mathematics, 17.12.2020 21:50 supergirl101911

Every year in Delaware there is a contest where people create cannons and catapults designed to launch pumpkins as far in the air as possible. The equation below can be used to represent the height, y, of a launched
pumpkin, where x is the time in seconds that the pumpkin has been in the
air. What is the maximum height that the pumpkin reaches? How many
seconds have passed when the pumpkin hits the ground? (Hint: If the
pumpkin hits the ground. its height is O feet.)

y = 15 + 110x – 16x^2

A-The pumpkin's maximum height is 204.06 feet and it hits the ground after 7.01
seconds.

B-The pumpkin's maximum height is 3.44 feet and it hits the ground after 7.01 seconds.

C-The pumpkin's maximum height is 204.06 feet and it hits the ground after 3.44
seconds.

D-The pumpkin's maximum height is 3.44 feet and it hits the ground after 204.06
seconds.

Answers: 3

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