H(t)= (t+3)^2 + 5h(t)=(t+3) 2
+5h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plus, 5
What is the average rate of change of hhh over the interval -5\leq t\leq -1−5≤t≤−1minus, 5, is less than or equal to, t, is less than or equal to, minus, 1?

mnkjn

step-by-step explanation:

the answer is:

the lateral area is equal to

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

now, calculating the perimeter of the base, we have:

then, calculating the lateral area:

hence, we have that the lateral area is equal to

have a nice day!

ιт ωιℓℓ gσ

5,-10,20,-40,30,-60

нσρє ι ¢συℓ∂ нєℓρ

step-by-step explanation:

hihi so drawing these 2 triangles is fairly simple. all that's left is finding the height of each one. luckily, we have a side length and an angle, so there is a trig function we can use to solve for the height. the easiest one to use would be tangent, since we have 2/3 things needed to find and the third needed is what we are solving for. tan(73°) * 30 ~= 98.13 and tan(73°) * 35 ~= 114.45