Given the point (3,-4) & slope = 2, what is the equation of the line?

Step-by-step explanation:

So use the point slope formula: y-y1=m(x-x1)

substitute y1 and x1 with the points and m with the slope: y-(-4)=2(x-3)

y+4=2(x+3).

This is Point-slope form.

you can go on if you want: y+4=2x+6(I multiplied 2 by x and 3)

subtract 4 from both sides: y=2x+2

This is slope-intercept form.

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

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