Suppose that the radius of the base of a cone is R. Suppose, moreover, that the volume of the cone is the same as the volume of the sphere with radius R (same as the base radius of
the cone). How many times is the height of the cone larger than R?

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)