Find the slope of the line passing through the given points using the slope formula. Describe the slope as positive, negative, zero or undefined. (5, 3) and (10,8)

slope=1

(second y -first y )÷(sec x-first x)

so (8-3)/(10-5)=1

so 1 is positive

i would like to give you this hope this can help you memerize slope

the pic :

if the line ascending from the left to the right its for positive slope

if the line ascending from the right to the left its for negative slope

if the line straight down (if you see the pic its has infinity simbol) its means undefined

if the the line straight horizontoal its means the slope os zero

im sorry bcs i have bad eng

hope this will help you

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.