Jamie rolls a 6-sided die 30 times and determines that the experimental probability of rolling a 2 is StartFraction 1 over 15 EndFraction. The theoretical probability of rolling a 2 is StartFraction 1 over 6 EndFraction. What could Jamie do to make his experimental results more closely match the theoretical probability? He can increase the number of trials. He can decrease the number of trials. He can increase the number of sides on the die. He can decrease the number of sides on the die.

is should be y = 5x

step-by-step explanation:

correct me if im wrong

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.