Can anyone help me ?

m∠T = 48°

ΔMAT has MA = MT

=> ΔMAT is a isosceles triangle at M

=> ∠A = ∠T = (180° - ∠M)/2

=> x + 20  = (180 - 3x)/2

⇔ 2x + 40 = 180 - 3x

⇔ 5x = 140

⇔ x = 140/5

⇔ x = 28

=> ∠A = ∠T = 28 + 20 = 48°

Step-by-step explanation:

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: