Given the functions f(x)=6x-3 and h(x)=10x+5, find the value of x for which f(x)=h(x)

The functions equal each other when x=-2.

Step-by-step explanation:

Setting the functions equal to each other gives you:

6x-3=10x+5.

Consolidating the variables and constants, you get:

4x=-8.

Solving for x gives you:

x=-2.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752