Solve:
5^x+1/5^x=25 1/25

either x=2 or x=-2

Step-by-step explanation:

let 5^x be a then,

a+1/a=626/25

or,25(a^2+1)=626a

or,25a^2+25-626a=0

or,25a^2-626a+25=0

or,25a^2-(625+1)a+25=0

or,25a^2-625a-a+25=0

or,25a(a-25)-1(a-25)=0

or,(a-25)(25a-1)=0

either,

a-25=0

or,a=25

or,5^x=5^2

equating the powers we get,

x=2

or,

25a-1=0

or,a=1/25

or,5^x=1/5^2

or,5^x=5^-2

equating the powers we get,

x=-2

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

sorry i got nothing

step-by-step explanation: