How to i find out what BAC equals?

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  angle BAC = 35°

Step-by-step explanation:

The measure of an inscribed angle is half the measure of the arc it intercepts. Arc BC is 70°, so inscribed angle BAC is half that, or 70°/2 = 35°.

In this geometry, you can find angle BAC a couple of ways.

Any triangle inscribed in a semicircle is a right triangle. That is, AB is a diameter, so angle ACB intercepts half the circle (180°). Half that measure is 90°. Then angles ABC and BAC are complementary:

  angle BAC = 90° -55° = 35°

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

idk

step-by-step explanation: i just don't