Help please Someone please I neeed

The minimum value of f(x) is 2

Step-by-step explanation:

∵ f(x) = 2x² - 4x + 4

→ Find f'(x)

∵ f'(x) = 2(2) - 4(1) + 0

∴ f'(x) = 4x - 4

→ Equate f'(x) by 0

∵ f'(x) = 0

∴ 4x - 4 = 0

→ Add 4 to both sides

∵ 4x - 4 + 4 = 0 + 4

∴ 4x = 4

→ Divide both sides by 4

∴ x = 1

→ The minimum value is f(1)

∵ f(1) = 2(1)² - 4(1) + 4

∴ f(1) = 2 - 4 + 4

∴ f(1) = 2

∴ The minimum value of f(x) is 2

idk

step-by-step explanation:

do it yourself, cause that made me do it myself today, in english!

0 is its x and y coordinate