I need help with math homework

A. (0, 1) and (2, -2)

B. Slope (m) = -³/2

C. y + 2 = -³/2(x - 2)

D.

E.

Step-by-step explanation:

A. Two points on the line from the graph are: (0, 1) and (2, -2)

B. The slope can be calculated using two points, (0, 1) and (2, -2):

Slope (m) = -³/2

C. Equation in point-slope form is represented as y - b = m(x - a). Where,

(a, b) = any point on the graph.

m = slope.

Substitute (a, b) = (2, -2), and m = -³/2 into the point-slope equation, y - b = m(x - a).

Thus:

y - (-2) = -³/2(x - 2)

y + 2 = -³/2(x - 2)

D. Equation in slope-intercept form, can be written as y = mx + b.

Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.

y + 2 = -³/2(x - 2)

2(y + 2) = -3(x - 2)

2y + 4 = -3x + 6

2y = -3x + 6 - 4

2y = -3x + 2

y = -3x/2 + 2/2

E. Convert the equation in (D) to standard form:

i need on these three questions. find standard form equation of line perpendicular to y = (2/3)x - 8 that goes through the point

the equation of a line is -6x-2y=-18 what is the x 3 answers sep 21, 2015

finding the critical point for f(x,y)=(x^2)*y+y^3 1 answer mar 10, 2013

more results from answers.yahoo.com

step-by-step explanation:

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632