I need help with math homework #2 algebra

A. (0, -2) and (4, 1)

B. Slope (m) = ¾

C. y - 1 = ¾(x - 4)

D. y = ¾x - 2

E. -¾x + y = -2

Step-by-step explanation:

A. Two points on the line from the graph are: (0, -2) and (4, 1)

B. The slope can be calculated using two points, (0, -2) and (4, 1):

Slope (m) = ¾

C. Equation in point-slope form is represented as y - b = m(x - a). Where,

(a, b) = any point on the graph.

m = slope.

Substitute (a, b) = (4, 1), and m = ¾ into the point-slope equation, y - b = m(x - a).

Thus:

y - 1 = ¾(x - 4)

D. Equation in slope-intercept form, can be written as y = mx + b.

Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.

y - 1 = ¾(x - 4)

4(y - 1) = 3(x - 4)

4y - 4 = 3x - 12

4y = 3x - 12 + 4

4y = 3x - 8

y = ¾x - 8/4

y = ¾x - 2

E. Convert the equation in (D) to standard form:

y = ¾x - 2

-¾x + y = -2