Identify the equation in slope-intercept form for the line containing the point (2,4) and perpendicular to y=1/2x+1/2.

y = -2x + 8

Step-by-step explanation:

For this problem we need to consider that the equation of a line perpendicular to another line will have a "negative reciprocal" slope so that when they cross, it forms a 90-degree angle, hence perpendicular.  Additionally, we will need to use the point-slope form and re-write it into the slope-intercept form to incorporate (2,4) into our equation.  With these things in mind, let's do that.

y = (1/2)x + (1/2)

We want a "negative reciprocal" so:

y = -2x + (1/2)

Since -2 is the "negative reciprocal" of 1/2.

And now we want to use the point-slope form to incorporate (2,4)

y - y0 = -2 ( x - x0 )

Where, y0 = 4 and x0 = 2.

y - y0 = -2 ( x - x0 )

y - 4 = -2 ( x - 2 )

y - 4 = -2x + 4

y = -2x + 8

So, the equation that is perpendicular to y = (1/2)x + (1/2) and includes the point (2,4) is y = -2x + 8.

Cheers.

she will most likely have 33  

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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