An airline charges an extra fee if a suitcase weighs more than 50 pounds. After packing, Li's suitcase weighs 47.75 pounds. Which inequality can be used to determine how much more weight can be added to the suitcase without going over the 50-pound weight limit? 47.75 + x < 50 47.75 + x Less-than-or-equal-to 50 47.75 + x Greater-than-or-equal-to 50 47.75 + x > 50

47.75 + x Less-than-or-equal-to 50

= 47.75 + x ≤ 50

Step-by-step explanation:

Solving the above Question:

Not going over the 50 pound case mean, less than or equal to 50 pounds

Let the extra pound of weight be represented as x

Hence, the inequality equation that can be used to determine how much more weight can be added to the suitcase without going over the 50-pound weight limit =

47.75 + x ≤ 50

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)