WILL GIVE BRAINLIESt: Given: ∆ABC, AC = 5

m∠C = 90°

m∠A = 22°

Find: Perimeter of ∆ABC

Perimeter of ΔABC is 12.41 units.

From the picture attached,

Since, cosθ = and sinθ =

For angle A,

Adjacent side = AC = 5 units

Opposite side = BC

and Hypotenuse = AB

By substituting the values in the cosine ratio,

cos(22°) =

AB =

      = 5.39

Since, sinθ =

sin(22°) =

BC = 5.39[sin(22°)]

     = 2.02

Since perimeter of the given triangle ABC = AB + BC + AC

By substituting the measures of all sides in the expression of the perimeter,

Perimeter = 5.39 + 2.02 + 5

                 = 12.41 units.

         Therefore, perimeter of the given triangle is 12.41 units.

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hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

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