alex has a 48 mile trail first half of the time he was biking twice as fast as the second half of the time if he spent 4 hours on the road how fast was he biking at first

16 mph

Step-by-step explanation:

Givens:

4 hours total time

48 miles total distance

So our equation should look like this.

48 = 2x(2) + x(2)

Where x = speed second half of trip.

x = 8

x*2 = 16 mph

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

use google you idiot omg you're so annoying

step-by-step explanation: