Can triangles ΔAJB and ΔCBJ be proven congruent by SAS?

Please help will mark brainliest

YES

Step-by-step explanation:

Since AJ and BD are parallel to each other, therefore, <CBJ = <AJB. Both angles are alternate interior angles.

Thus, two sides, AJ and JB and an included angle, <AJB, of ∆AJB, are equal to two sides, BC and JB, and an included angle, <CBJ of ∆CBJ. Therefore, ∆AJB and ∆CBJ are congruent to each other by the SAS Congruence Theorem.

only 10/60 isn't equivalent

hope this : )

answer: 0,6

step-by-step explanation:

this would make it the y intercept.