Complete the proof by providing the missing statement and reasons Given: SD ⊥ HT; SH ≅ ST
Prove: ΔSHD = ΔSTD

2. angle bisector splits into even halves

Step-by-step explanation:

that's all i can assist with sorry, proofs still confuse me!

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

i have no idea just need points sorry

step-by-step explanation: