A line passes through A(6,5) and B(4,2) find equation of a line parallel to AB and passes through (7,10)

2y = 3x-1

Step-by-step explanation:

We start by calculating the slope of AB

m = (y2-y1)/(x2-x1) = (2-5)/(4-6) = 3/2

Since the two lines are parallel, then their slopes are equal

We use the point-slope form to get the equation

That will be;

y-y1 = m(x-x1)

y-10 = 3/2(x-7)

y = 3x/2-21/2+ 10

Multiply through by 2

2y= 3x -21 + 20

2y = 3x-1

1. 34

2. 268

3. x=14.4

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.