Sheila leaves on a trip driving at 30 miles per hour. Two hours later, her sister Allison leaves from the same location driving at 45 miles per hour. How long after Allison leaves home will she catch up to Sheila? 4 hours

6 hours

5 hours

2 hours

Step-by-step explanation:

Let t = time on the road when A catches up with S

Then (t+2) = time S is on the road, when A catches up

:

We know that when A catches S, they will have traveled the same distance.

We can write a distance equation from that fact: Distance = speed * time

:

A's dist = S's distance

60t = 30(t+2)

60t = 30t + 60

60t - 30t = 60

30t = 60

t = 60/30

t = 2 hrs for A to catch up with S

It will take 6 hours for Allison to catch up to Sheila.

Step-by-step explanation:

The equation for the problem is 60x=45x+90. You would then have to subtract 45x from both sides.

15x=90 Then you would divide both sides by 15x.

x=6

three-fourths of an hour

36÷48=0.75

0.75=

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation: