How should this problem be solved? (a3)2 a. a3 + 2 = a5 b. a3 ÷ 2 = a1.1 c. a3 – 2 = a1 d. a3 x 2 = a6

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

the answer is d

step-by-step explanation:

you can also use mathway to get you answer + steps