You have a bag of enough ping pong balls such that each one has exactly one of the numbers from 57 to 133 painted on it. What is the probability that if you randomly select five of the balls from the bag all of the numbers on the selected balls will be divisible by 3 or by 7?

Using the hypergeometric distribution, it is found that there is a 0.0128 = 1.28% probability that if you randomly select five of the balls from the bag all of the numbers on the selected balls will be divisible by 3 or by 7.

The balls are chosen without replacement, hence, the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Multiples in the interval:

Hence,

As for the other parameters:

The probability is P(X = 5), hence:

0.0128 = 1.28% probability that if you randomly select five of the balls from the bag all of the numbers on the selected balls will be divisible by 3 or by 7.

A similar problem is given at link

The answer is "0.338"

Step-by-step explanation:

We have 133-57+1 = 77 balls to pocket, essentially.  See the number of words around 57 and 133 and separable by 3 (132):

Therefore, the number for a number around 57 and 133 divisible by 3 = 26  

The probability required

3/6 chance

step-by-step explanation:

half of the nubers are odd numbers (1,3,5) which in that case if you would be told to simplify it would be 1/2

step-by-step explanation:

your answer is a