A polynomial has been factored, as shown below: f(x) = (x - 9)(x + 12)(x - 24)
What are the zeros of the polynomial?
1)-9,9, -12, 12, -24, 24
2) -9, 12, -24
3) 9.-12, 24
4) 9, 12, 24

To find the zeros of a polynomial, you make every factored parentheses equal to zero. You basically make the other side equal to zero and solve for x.

So,

Your zeros are x = 9, -12, 24

So your answer is 3) 9, -12, 24

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: