How would you graph the solution to 3x<-15? O Draw an open circle on -5 and shade to the left.
O Draw an open circle on -5 and shade to the right.
O Draw a closed circle on -5 and shade to the left.
O Drawa closed circle on -5 and shade to the right.

Drawn an open circle on -5 and shade to left.

Step-by-step explanation:

To determine if the circle should be closed or not:

 If the equation has < or >, the circle should be opened.

Where to shade:

Since the x is on the left side of the equation, it's telling you to shade the direction that the sign is pointing at, which is left ( < ). If x was on the right side of the equation, it's telling you to shade the part where the sign is not pointing at.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!