A triangle has one side that measures 5 units and another side that measures 7 units. What are two possible lengths for the third side?
Explain why you chose the lengths you did.

see explanation

Step-by-step explanation:

Given 2 sides of a triangle then the third side x is between the limits

difference of 2 sides < x < sum of 2 sides, that is

7 - 5 < x < 7 + 5 , then

2 < x < 12

Choose any 2 values between 2 and 12 as third side, so

third side could be 6 or 9 for example

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option