If f(x)= x^2-6x-14 find the value of f(-2) (I prefer some kind of help rather than an answer, but answers are welcome)

Step-by-step explanation:

In order to figure out what is f(-2), we substitute all the "x" in the function with "-2" like this:

f(-2) = x² - 6x - 14 = (-2)² - 6(-2) -14

Now we can follow PEMDAS:

(-2)² - 6(-2) -14

= 4 + 12 - 14

= 2.

Hence, f(-2) = 2.

the answer to the question is a  

it has the same slope and the same y-intercept.

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: