Find three consecutive integers such that 3 times the first added to the last is 22.

5,6,7

Step-by-step explanation:

consetive integers are 1 apart

they are

x,x+1,x+2

3 times the first added to the last is 22

3x+x+2=22

combine like terms

4x+2=22

minus 2 both sides

4x=20

divide both sides by 4

x=5

x+1=6

x+2=7

the numbers are 5,6,7

5,6,7

Step-by-step explanation:

hope this helps :)

109 trust me

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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