Find three consecutive even integers such that the sum of the second and third is 3 times the first integer.

, and

Step-by-step explanation:

Let smallest consecutive even integer.

Since the second and third consecutive even integers can be expressed by our smallest even consecutive integer, we can express them as:

Second consecutive even integer =

Third consecutive even integer =

From "the sum of the second and third is 3 times the first integer", we can write:

(collect like-terms)

∴ The first consecutive even integer is 6

Now, we can use substitution to find the values of the second and third consecutive even integers:

Second consecutive integer =

Third consecutive integer =

∴ The three consecutive even integers are , and .

Hope this helps :)

huh? im pretty sure it is in 199

step-by-step explanation:

geometry: triangles

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answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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