I need help before with this before 12:00 am Distances in space are measured in light-years. The distance from Earth to a star is 6.8 × 1013 kilometers. What is the distance, in light-years, from Earth to the star (1 light-year = 9.46 × 1012 kilometers)?

2.66 light-years
7.18 light-years
7.74 light-years
9.46 light-years

7.18 light-years

Step-by-step explanation:

6.8 x 10^13 = 68,000,000,000,000

9.46 x10 ^12 = 9,460,000,000,000

6.8 x 10^13  *  1 light year / 9.46 x 10^12 = 7.188 light years.

Have a Merry X-MAS Plz MArk Branilest

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )