In order to solve the following system of equations by subtraction, which of the following could you do before subtracting the equations so that one variable will be eliminated when you subtract them? 4x-2y=7
3x-3y=15

A. Multiply the top equation by-3 and the bottom equation by 2
B. Multiply the top equation by 1/3
C. Multiply the top equation by 15 and the bottom equation by 7
D. Multiply the top equation by 3 and the bottom equation by 4.

9514 1404 393

  D.  Multiply the top equation by 3 and the bottom equation by 4.

Step-by-step explanation:

If you're using subtraction, you want the coefficients of one of the variables to be the same in both equations. If the variable you choose is x, then you need to multiply the top equation by the coefficient of x in the bottom equation (3), and the bottom equation by the coefficient of x in the to equation (4). Doing this will make both x-coefficients equal to 3×4 = 12. In short, ...

  Multiply the top equation by 3 and the bottom equation by 4.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

is this part of a question or something