WILL GIVE BRAINLIST AND PLS INCLUDE HOW YOU SOLVED IT! The relationship between altitude and the boiling point of a liquid is linear. At an altitude of 8200 it, the liquid boils at
195.42°F. At an altitude of 4300 ft, the liquid boils at 202.83F. Write an equation giving the boiling point b of the liquid,
in degrees Fahrenheit, in terms of altitude a, in feet. What is the boiling point of the liquid at 2500 it?
Write an equation

b = -0.0019a + 211

at a=2500, b=215.75

Step-by-step explanation:

The points we get from the problem are

(8200 , 195.42)

(4300, 202.83)

where a= altitude and b=boiling point in degrees F

to find slope by b2-b1 / a2-a1

(202.83 - 195.42) / (4300-8200)

= 7.41 / -3900

= -0.0019

we have b = -0.0019a + intercept

substitute in one point to figure out intercept

195.42 = -0.0019(8200) + intercept

195.42 = -15.58 + intercept

add 15.58 to both sides

195.42 + 15.58 = -15.58 + 15.58 + intercept

intercept = 211

b = -0.0019a + 211

At an altitude of 2500ft (a=2500) find b.

b = -0.0019(2500) + 211

b = 4.75 + 211 = 215.75

b = 215.75 degrees F

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(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180