What is the slope of a line perpendicular to the line whose equation is 6x-15y=270

m= -2 1/2

Step-by-step explanation:

First, let's put the equation into slope intercept form.

6x-15y=270

-15y=-6x+270

y=6/15x+270

For two lines to be perpendicular, their slopes must be opposite reciprocals.

m=-15/6 or m= -2 1/2

slope = -

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

6x - 15y = 270 ( subtract 6x from both sides )

- 15y = - 6x + 270 ( divide all terms by - 15 )

y = x - 18, that is

y = x - 18 ← in slope- intercept form

with slope m =

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = -

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1